
4
IV. DYNAMICS OF OSCILLATION
Narrative: Why do neutrinos oscillate? A charged lepton is ”anchored” or pinned to the
lattice by the strong bulk tension, forcing it into a specific geometric state (Point, Line, or Plane).
It behaves like a localized particle. A neutrino, being unanchored, is not pinned. It behaves like a
wave in a dispersive medium. When a neutrino is created, it is a wave packet composed of different
polarization modes (geometric harmonics). Because the lattice has microstructure, these modes
travel at different speeds. As they propagate, they drift out of phase, creating the beating pattern
we measure as oscillation.
Formalism: The equation of motion for the free microrotation field ϕ is derived from the
variation of Eq. (2):
ρJ
¨
ϕ − γ∇
2
ϕ + 4κϕ = 0 (8)
where J ∼ ℓ
2
P
is the micro-inertia density, representing the geometric size of the rotating nodes.
This is a wave equation with a dispersive mass term 4κ. The dispersion relation ω(k) depends on
the twist modulus γ. Crucially, in the FCC lattice, the twist modulus is anisotropic for different
geometric modes (Point/Line/Plane harmonics).
∆m
2
ij
∼
γ
i
− γ
j
J
(9)
The flavor state |ν
α
⟩ is a coherent superposition of these mass eigenstates. The oscillation proba-
bility is governed by the beat frequency determined by the anisotropy of γ.
V. CHIRALITY AND DIRAC NATURE
Narrative: Why are neutrinos left-handed? In our model, weak interactions happen at
the ”corners” of the vacuum structure (triangular faces). These corners are geometrically frus-
trated—they have a built-in twist (C
3
symmetry). When a neutrino is created here, the lattice
forces it to twist in the same direction as the local geometry. A ”right-handed” neutrino would be
a twist against the grain, which the lattice forbids. Also, a twist is topologically different from an
anti-twist (like a screw thread). Therefore, the neutrino and anti-neutrino are distinct particles.
Formalism: The coupling term in the Lagrangian is κ(∇ × u − 2ϕ)
2
. This term converts
orbital angular momentum (∇ × u) into spin (ϕ). On a triangular lattice face, the curl operator
∇×u breaks parity due to the C
3
frustration. This parity breaking selects a single chirality for the